Алгоритм преобразования десятичной дроби в двоичную в языке C#

static void Main(string[] args)
        {
            int number;
            Console.Write("Enter a Number : ");
            number = int.Parse(Console.ReadLine());
            int q;
            string rem = "";
            while (number >= 1)
            {
                q = number / 2;
                rem += (number % 2).ToString();
                number = q;
            }
            string binary = "";
            for (int i = rem.Length - 1; i >= 0; i--)
            {
                binary = binary + rem[i];
            }
            Console.WriteLine("The Binary format for {0} is {1}",number, bi

static void Main(string[] args)

{

int number;

Console.Write("Enter a Number : ");

number = int.Parse(Console.ReadLine());

int q;

string rem = "";

while (number >= 1)

{

q = number / 2;

rem += (number % 2).ToString();

number = q;

}

string binary = "";

for (int i = rem.Length - 1; i >= 0; i--)

{

binary = binary + rem[i];

}

Console.WriteLine("The Binary format for {0} is {1}",number, bi

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